Differentiating trigonometric functions
Differentiate , and ; apply the chain rule to differentiate , and .
Worked examples
Standard derivatives
Straightforward
Problem
Find for .
1
Recall the three fundamental trigonometric derivatives (all angles in radians).
2
Differentiate each term of .
Answer
Chain rule with trigonometric functions
Moderate
Problem
Find .
1
Identify the inner function.
Inner function: , so .
2
Differentiate using the chain rule.
Answer
Finding stationary points
Challenging
Problem
Find the stationary points of for .
1
Differentiate.
2
Set the derivative equal to zero.
3
Solve for .
or (within ), so
4
Find the -values.
At : (maximum). At : (minimum).
Answer
The stationary points are a maximum at and a minimum at .
Practise
Q1·Straightforward
What is ?
Explanation
The standard result: .
All angles are measured in radians for this rule to hold.
All angles are measured in radians for this rule to hold.
Q2·Straightforward
What is ?
Explanation
The standard result: .
The negative sign is easy to forget — note that differentiating twice cycles back: .
The negative sign is easy to forget — note that differentiating twice cycles back: .
Q3·Straightforward
What is ?
Explanation
The standard result: .
Recall that , so .
Recall that , so .
Q4·Straightforward
Using the chain rule,
Explanation
Let , so .
Q5·Straightforward
Find .
Explanation
Q6·Moderate
Find .
Explanation
Let , so .
Q7·Moderate
Find the gradient of at . Give an exact answer as a decimal to 2 decimal places.
Explanation
.
At : .
At : .
Q8·Moderate
Find .
Explanation
Q9·Moderate
Find .
Explanation
Let , so .
Q10·Moderate
The function has a stationary point in the interval . Find the -value (in radians) of the first stationary point to 3 decimal places.
Explanation
.
Set : , so
In , the first solution is , giving:
Set : , so
In , the first solution is , giving:
Q11·Challenging
Find the gradient of at . Give your answer to 3 decimal places.
Explanation
.
At :
At :
Q12·Challenging
Find for .
Explanation
First derivative: .
Second derivative: .
Note: , which means satisfies a simple harmonic equation.
Second derivative: .
Note: , which means satisfies a simple harmonic equation.
Q13·Challenging
A particle moves so that its displacement is metres at time seconds. Find the velocity (in m/s) of the particle at seconds.
Explanation
.
At :
The negative sign means the particle is moving in the negative direction.
At :
The negative sign means the particle is moving in the negative direction.
Open Math
Differentiating trigonometric functions
Calculus · MAV-12-04
Name:
Date:
Q1Straightforward
What is ?
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Q2Straightforward
What is ?
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Q3Straightforward
What is ?
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Q4Straightforward
Using the chain rule,
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Q5Straightforward
Find .
- A.
- B.
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- D.
Q6Moderate
Find .
- A.
- B.
- C.
- D.
Q7Moderate
Find the gradient of at . Give an exact answer as a decimal to 2 decimal places.
Q8Moderate
Find .
- A.
- B.
- C.
- D.
Q9Moderate
Find .
- A.
- B.
- C.
- D.
Q10Moderate
The function has a stationary point in the interval . Find the -value (in radians) of the first stationary point to 3 decimal places.
Q11Challenging
Find the gradient of at . Give your answer to 3 decimal places.
Q12Challenging
Find for .
- A.
- B.
- C.
- D.
Q13Challenging
A particle moves so that its displacement is metres at time seconds. Find the velocity (in m/s) of the particle at seconds.
Worked solutions and answers at openmath.au/year-12/advanced/differential-calculus/differentiating-trigonometric-functions