Mathematical induction
Worked examples
Summation formula
Straightforward
Problem
Answer
Divisibility proof
Moderate
Problem
Answer
Inequality proof
Challenging
Problem
Answer
Practise
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
LHS . RHS . ✓
**Inductive hypothesis:** Assume is true for some integer :
**Inductive step:** We must show is true, i.e., .
Starting from the left-hand side of :
This is exactly the RHS of . ✓
**Conclusion:** By the principle of mathematical induction, is true for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
LHS . RHS . ✓
**Inductive hypothesis:** Assume is true:
**Inductive step:** Show is true.
The next odd number in the sequence is . Adding it:
This equals , the RHS of . ✓
**Conclusion:** By the principle of mathematical induction, is true for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
. Divisible by 5. ✓
**Inductive hypothesis:** Assume is true: for some integer , i.e., .
**Inductive step:** Show is true, i.e., .
Since is an integer, is divisible by 5. ✓
**Conclusion:** By the principle of mathematical induction, for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
. Divisible by 3. ✓
**Inductive hypothesis:** Assume is true: for some integer , so .
**Inductive step:** Show .
Since is an integer, is divisible by 3. ✓
**Conclusion:** By the principle of mathematical induction, for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
LHS . RHS . ✓
**Inductive hypothesis:** Assume is true:
**Inductive step:** Show is true.
This equals , which is the RHS of . ✓
**Conclusion:** By the principle of mathematical induction, is true for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
. Divisible by 3. ✓
**Inductive hypothesis:** Assume is true: for some integer .
**Inductive step:** Show .
Expand:
By the inductive hypothesis, , so:
This is divisible by 3. ✓
**Conclusion:** By the principle of mathematical induction, for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
LHS . RHS . ✓
**Inductive hypothesis:** Assume is true:
**Inductive step:** Show is true.
Factoring the quadratic: .
This equals , the RHS of . ✓
**Conclusion:** By the principle of mathematical induction, is true for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
. ✓
**Inductive hypothesis:** Assume is true for some : .
**Inductive step:** Show is true, i.e., .
From the inductive hypothesis:
Multiply both sides by 2 (both sides are positive):
Now observe that for :
(since ).
Therefore:
So . ✓
**Conclusion:** By the principle of mathematical induction, for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
. Divisible by 6. ✓
**Inductive hypothesis:** Assume is true: for some integer .
**Inductive step:** Show .
(This uses the identity , i.e., .)
By the inductive hypothesis, , so:
Now and are consecutive integers, so one of them must be even. Therefore is divisible by 2, and is divisible by 6.
Let for some integer . Then:
Divisible by 6. ✓
**Conclusion:** By the principle of mathematical induction, for all integers .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Base case** ():
. ✓
**Inductive hypothesis:** Assume is true for some : .
**Inductive step:** Show is true, i.e., .
From the inductive hypothesis:
Multiply both sides by 3:
Now check: for :
(since for all ).
Therefore:
So . ✓
**Conclusion:** By the principle of mathematical induction, for all integers .
Open Math
Mathematical induction
Proof · ME-12-01
Worked solutions and answers at openmath.au/year-12/extension-1/proof-by-mathematical-induction/mathematical-induction