Geometric proof with vectors
Worked examples
Proving a quadrilateral is a parallelogram
Straightforward
Problem
Answer
Angle in a semicircle
Moderate
Problem
Answer
Medians of a triangle are concurrent
Challenging
Problem
Answer
Practise
Explanation
This confirms that is the midpoint of , and , , are collinear.
Explanation
The -coordinate of is .
Explanation
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
Compute :
Compute :
Since , the sides and are equal in length and parallel.
Therefore is a parallelogram.
**Note:** This result (Varignon's theorem) holds for any quadrilateral — including non-planar ones in 3D — because the proof uses no assumption about the shape or planarity of .
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
Compute :
Since :
- is parallel to (they are scalar multiples of the same vector), and
- .
This is the **Midsegment Theorem**: the segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Midpoint of :**
**Midpoint of :**
Since , both diagonals pass through the same midpoint.
Therefore the diagonals of a parallelogram bisect each other.
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
Compute the dot product:
Since , the angle .
**Geometric statement:** The angle in a semicircle is always a right angle.
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
**Point dividing in ratio from :**
**By symmetry**, the point dividing the median from to the midpoint of in ratio from gives the same expression , and likewise for the median from .
All three medians pass through the same point , so they are concurrent. This point is the **centroid**.
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
Using :
Since :
Therefore and are perpendicular.
**Geometric interpretation:** In a rhombus, and are the two diagonals. This result proves that the diagonals of a rhombus are always perpendicular.
✎ Work this one through on paper — proofs are self-assessed.
Worked proof
For any scalars :
Since the dot product is zero, is perpendicular to for all scalars .
**Geometric meaning:** If is perpendicular to two non-parallel vectors and , then is perpendicular to the entire plane spanned by and .
Open Math
Geometric proof with vectors
Vectors · MEX-12-05
Worked solutions and answers at openmath.au/year-12/extension-2/further-work-with-vectors/geometric-proof-with-vectors